Brakes applied to a car produces an acceleration of 6m/s in the opposite direction to the motion. If the car takes 2s to stop after the application of brakes, Calculate the distance it travels during this time pls very urgent pls answer ;(
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if the car take 2 second to stop after the application of break, calculate the distance its travel during this time ? 2. See answers.
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Answer:
a= -6m/s^2 (opposite direction)
t=2s
v=0
v=u+at
0=u+2(-6)
-u=-12
u=12m/s
s=ut+1/2at^2
s=12x2+1/2x-6x2x2
s=24+1/2x-24
s=24+(-12)
s=12m
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