brakes applied to car produce a uniform retardation of 90 cms^2 if the car was traveling with the velocity of 27 ms^1 then what distance will it cover before coming to rest
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Explanation:
Given : a = -0.9m/s² (because its retardation)
v = 0 (Because in the final, the car stops)
u = 27m/s (its already given)
To find : Distance 'd'
Solution : The formula we will be using is -
V²=U²+2as
So,
(0)²= (27)²+2(-0.9)(s)
0 = 729 +( -1.8)(s)
=> 1.8s = 729
=> s = 729/1.8
So, the answer is s = 405 metres
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