Brakes are applied to a car produce a uniform retardation of 0.9m/s^2,if initial velocity of car is 27m/s^2,what distance will it cover before coming to rest?
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Answer:
dist travelled before coming to rest = 405 m
Explanation:
u = 27 m/s
a = -0.9 m/sq-sec
v = 0
so, using 3rd eqn of motion -
v^2 = u^2 + 2as
s = (v^2 - u^2)/2a
= (0 - 27×27)/(2×(-0.9))
= 405 m
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hope, it helps you.
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