Brakes are applied to a car travelling at 30m/s its velocity is reduce to 20m/s in 5sec calculate the distance its travel
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hey dear
here is your answer
given data :
initial velocity (u) = 30 m/s
final velocity (v) = 20 m/s
time taken (t) = 5 seconds
to find : distance travelled (s)
solution :
by using first equation of motion
v = u+at
20 = 30+5a
5a = -10
a = -2 m/s²
by using second equation of motion
s = ut+1/2at²
s = 30*5+1/2*(-2)*(5)²
s = 150-25
s = 125 meter
hope it helps :)
here is your answer
given data :
initial velocity (u) = 30 m/s
final velocity (v) = 20 m/s
time taken (t) = 5 seconds
to find : distance travelled (s)
solution :
by using first equation of motion
v = u+at
20 = 30+5a
5a = -10
a = -2 m/s²
by using second equation of motion
s = ut+1/2at²
s = 30*5+1/2*(-2)*(5)²
s = 150-25
s = 125 meter
hope it helps :)
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