Question

Brakes are applied to a moving truck to produce retardation of 5 metre per second square is the time taken between application of brakes and the truck stop is 2 seconds calculate the distance travelled by the truck during this time. Please answer this​

Answer 1

Answer:

10 meters

Explanation:

use SUVAT equations:

v=u +at

s=ut+1/2at2

v2=u2+2as

s={(v+u)t}/2  where s-displacement

                                v-initial velocity

                                 u-final velocity

                                 a-acceleration/

                                      deceleration

                                t-time

in this question we have:

t= 2s   a=5m/s2  and,  final velocity= om/s                                                                                                  (after the car stops)

Therefore will use:  s=ut + 1/2at2

                            s= 0 x 2 + 1/2 x 5 x 2(squared)

                              =0 + 1/2 x 5 x 4

                              =1/2 x 20

                              =10

distance =  10 meters.

Answer 2

Explanation:

t=2s a=5m/s2 v=0m/s

s=ut+at2

s=0+1/2*5*2*2

s=0+10

s=10 m