Question

Brakes are applied to a moving truck to produce retardation of 5m/s2. If the time taken between application of brakes and the truck to stop is 2 seconds, calculate the distance travelled by the truck during this time

Answer 1

In this question, you use the SUVAT equations:

v=u +at
s=ut+1/2at2
v2=u2+2as
s={(v+u)t}/2  where s-displacement
                                 v-initial velocity
                                  u-final velocity
                                  a-acceleration/
                                       decceleration
                                 t-time
in this question we have:
t= 2s   a=5m/s2  and,  final velocity= om/s                                                                                                  (after the car stops)
Therefore will use:  s=ut + 1/2at2
                             s= 0 x 2 + 1/2 x 5 x 2(squared)
                               =0 + 1/2 x 5 x 4
                               =1/2 x 20
                               =10
therefore the distance covered =  10meters.