Question

brakes are applied to a moving truck to produce retardation of 5m/s2 . If the time taken between application of brakes and the truck to stop is 2 seconds , calculate the distance travelled by the truck during this time

Answer 1

retardation= 5m/s2
time=2 second
initial velocity =X
final velocity =0 (since the truck applies brake and stops)
initial velocity(u)
final velocity (v)
acceleration (a)
time (t)
distance(s)

u=v - at
x=0 - (-10×2)
x=20

s=v2-u2/2a (2 implies square)
s=0-400/2×(-10)
s=-400/-20
s=20m

(I am not sure about the calculation please do check) hope it helps

Answer 2

Answer:

retardation(a)= -5 m/s²

time(t) =2

initial velocity(u)=x

final velocity (v)=0

Explanation:

by using equation of motion v=u+at

0=x+(-5×2)

0=x+(-10)

0+10 =x

x =10m