Question

brakes are applied to a train moving at 40 kilometre per hour if the train comes to stop after 1 minute calculate the retardation and the distance covered by the train after the brakes are applied

Answer 1

u=40km/h=100m/9sec
v=0m/sec
t=60sec

using 1st equation
v=u+at
0=100/9+60a
60a=-100/9
a=-100/9÷60
a=-5/27m/s^2

using 2 equation
s=ut+1/2at^2
s=100/9×60+1/2×-5/27×60×60
s=0.5 m

Answer 2

Answer:

retardation is -0.18 and distance is 342m.