brakes are applied to a train moving at 40 kilometre per hour if the train comes to stop after 1 minute calculate the retardation and the distance covered by the train after the brakes are applied
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u=40km/h=100m/9sec
v=0m/sec
t=60sec
using 1st equation
v=u+at
0=100/9+60a
60a=-100/9
a=-100/9÷60
a=-5/27m/s^2
using 2 equation
s=ut+1/2at^2
s=100/9×60+1/2×-5/27×60×60
s=0.5 m
v=0m/sec
t=60sec
using 1st equation
v=u+at
0=100/9+60a
60a=-100/9
a=-100/9÷60
a=-5/27m/s^2
using 2 equation
s=ut+1/2at^2
s=100/9×60+1/2×-5/27×60×60
s=0.5 m
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1
Answer:
retardation is -0.18 and distance is 342m.
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