brakes are applied to a train travelling at 72 km/h after passing over 200m its velocity is reduced to 36 km/h at the same rate of retardation, how much further will it go before it is brought to rest.
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158
Initial speed:- 72000m/3600s=20m/s
Final Speed:-36000m/3600s=10m/s
Distance travelled:- 200m
Let retardation=r
therefore, 100=400-400r(v^2=u^2+2as)
300=400r
r=3/4 m/s^2
Final speed =0
Initial speed= 10m/s
r=3/4m/s^2
therefore, using v^2=u^2+2as
0=100-3/2s
3/2s=100
s=100*2/3
s=66.6666667m
Final Speed:-36000m/3600s=10m/s
Distance travelled:- 200m
Let retardation=r
therefore, 100=400-400r(v^2=u^2+2as)
300=400r
r=3/4 m/s^2
Final speed =0
Initial speed= 10m/s
r=3/4m/s^2
therefore, using v^2=u^2+2as
0=100-3/2s
3/2s=100
s=100*2/3
s=66.6666667m
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10
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