Math, asked by rahulwk3051, 1 year ago

Brand x sells 21 oz. Bags of mixed nuts that contain 29% peanuts. To make their product they combine brand a mixed nuts which contain 35% peanuts and brand b mixed nuts which contain 25% peanuts. How much of each do they need to use?

Answers

Answered by Anonymous
2

Answer:

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Step-by-step explanation:

Let x=Amount of Brand A

Then 21-x=Amount of Brand B  

Amount of peanuts in Brand A and B before the mixture takes place has to equal the amount of peanuts in the final mixture, so our equation to solve is:  

0.35x+0.25(21-x)=21*0.29 get rid of parens (distributive law)

0.35x+5.25-0.25x=6.09 subtract 5.25 from each side  

0.35x+5.25-5.25-0.25x=6.09-5.25 collect like terms  

0.10x=0.84 divide each side by 0.10

x=8.4 oz---------------------------------Amount of Brand A needed

21-x=21-8.4=12.6-----------------------------Amount of Brand B needed  

CK

8.4*0.35+12.6*0.25=21*0.29

2.94+3.15=6.09

6.09=6.09

Answered by nazayahdmeyers
0

Answer:

Step-by-step explanation:

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