Math, asked by wahib2244, 8 months ago

Brandon is 5 years younger than jhonny .after ten years jhonny will be twice of as brandon was 5 years ago ,find their present ages

Answers

Answered by Anonymous
15

Answer:

Jhonny = 30 yrs.

Brandon = 25 yrs.

Step-by-step explanation:

Let the present age of Jhonny is x yrs.

Therefore, we have,

The present age of Brandon = (x-5) yrs.

After 10 yrs.,

Age of Jhonny = (x+10) yrs.

5 yrs. ago,

Age of Brandon = (x-5-5) = (x-10) yrs.

But, it's given that,

After 10 yrs. Jhonny will be twice of as Brandon was 5 yrs. ago.

Therefore, we have,

=> x + 10 = 2(x-10)

=> x + 10 = 2x - 20

=> 2x - x = 10 + 20

=> x = 30

Therefore, we have,

=> x - 5 = 30-5 = 25

Hence, the presen ages of Jhonny and Brandon are 30 yrs. and 25 yrs. respectively.

Answered by Sencredible
6

Answer: Present ages of Brandon and Johnny are 25 and 30 years respectively.

Let the age of Johnny be x, then age of Brandon = x - 5.

According to ques,

After ten years , johnny will be twice of as brandon was 5 years ago

x + 10 = 2(x -10)

x + 10 = 2x - 20

10 + 20 = 2x - x

x = 30

==>> present age of Johnny = x = 30 years

And present age of Brandon = x - 5 = 30 - 5 = 25 years.

Present ages of Brandon and Johnny are 25 and 30 years respectively.

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