Question

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Answer 1

Answer:

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refer the reference diagram uploaded above

Step-by-step explanation:

so here in an adjoining circle

O is the centre of circle

moreover

OB is the radius

so OB=25.cm

and OM is perpendicular drawn from point O on chord AB

so we know that

A perpendicular drawn from centre of circle on its chord bisects the chord

thus then

AM=MB

ie AB=2AM (1)

so OM=4 cm

so now as OM perpendicular to AB

Angle OMB=90 degrees

Using Pythagoras Theorem on Triangle OMB

we get

OB²=OM²+MB²

MB²=OB²-OM²

=(25)²-(4)²

=625-16

=609

taking square roots on both sides we get

MB=√609

so thus then

AB=2×√609 From (1)

hence length of chord is 2√609 cm.