Question

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radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm what is the length of the chord?​

Answer 1

Explanation:

As perpendicular from centre bisects the chord, Rightarrow CA=AD=20cm; ln(Delta) * O * A * D , O * D ^ 2 = O * A ^ 2 + A * D ^ 2 (Pythagoras thereom) Rightarrow OA^ 2 =OD^ 2 -AD^ 2; =25^ 2 -20^ 2; =625-400=22; Rightarrow OA=15cm OA is distance of chord from O.

This is only I collect id wrong I am sorry

Answer 2

Step-by-step explanation:

Given :

Radius of a circle is 25 cm.

Distance of its chord from the centre is 4 cm.

To find :

Length of the chord.

Solution :

Finding the perpendicular :-

=> AB = √AO² - BO²

=> AB = √25² - 4²

=> AB = √625 - 16

=> AB = 24.67 cm

Finding the length of chord :-

>> Length of chord = 2(Perpendicular)

=> 2 × 24.67

=> 49.34 cm

• Hence, the length of chord of the circle is 49.34 cm.