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radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm what is the length of the chord?
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Answer:
49.34 cm is the required length of the chord .
According to the Question
It is given that ,
Radius of circle OA = 25cm
Distance of its Chord from the centre ,BO =4cm
we need to calculate the length of the Chord.
So ,We will use here the Pythagoras Theorem .
AO² = BO² + AB²
Substitute the value we get
➻ 25² = 4² + AB²
➻ 625 = 16 + AB²
➻ 625-16 = AB²
➻ 609 = AB²
➻ AB = 24.67cm
As we know that distance of its Chord from the the centre is perpendicular bisector of the chord .
So, the length of the chord is twice AB
➻ Length of Chord = 2AB
➻ Length of Chord = 2×24.67
➻ Length of Chord = 49.34 cm
Hence, the length of the chord is 49.34 cm (approx)
by brainly user!♡
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