Question

Breadth of a rectangle is 3 metre less than its length. If we increase its length by 2m and
breadth by im then the area of rectangle thus obtained has area 17m' more than the area of
the former rectangle. Find the length and breadth of the former rectangle.​

Answer 1

Answer:

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so here we go

Step-by-step explanation:

let the length of the rectangle and breadth be y m respectively

so according to first condition

y=x-3 (1)

now we know that

area of rectangle=l×b

so if this is a condition

so area of rectangle with this condition=xy

=x(x-3)

=x square-3x

according to second condition

(x+2)(y-1)=17+x square-3x

ie xy-x+2y-2=17+x square-3x

ie xy+2x+2y=19+x square (2)

so substitute value of y from (1) in (2)

we get x(x-3)+2x+2(x-3)=19+x square

ie x square-3x+2x+2x-6=19+x square

so x square gets eliminated on both sides

we get now

-3x+4x=25

ie x=25

substitute value of x in (1)

you get y=22

thus dimensions of rectangle are 25m×22m

wherein length of rectangle is 25 m and its breadth is 22 m