Question

Break applied to a car produce a negative acceleration 6m/s .if the car takes 23 after applying the breaks , calculate the distance it travels during the time

Answer 1

V=u+at
0=u-138
u=138

Now
V^2=u^2+2as
0=19044-2×6×s
s=1588 approx

Answer 2

Answer:

12 m/s

Explanation:

acceleration = change in velocity /time taken      OR   a = v / t

velocity = acceleration x time                                                      

therefore, velocity = 6 m/sec * 2 sec

= 12 m/s

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