Question

break of mass 2 kg rests on a lump of moist clay if the sides of its base are 10 cm and 5 cm calculate the pressure on the clay in SI units and CGS units​

Answer 1

Answer:

Explanation: The defination of the pressure is given as,

   $p = \frac{F}{A}$

Where, p is pressure,

             F is force,here force due to block which is mg

            F = 2*10 = 20 N

             A is the area

A = a*b

Where, a and b are base sides of block

A= 0.1*0.05 = 0.005 $m^{2}$

$p = \frac{20}{0.005}$

 In SI unit

      $p=4*10^{3} Pa$

In CGS unit

            1 Ba = 0.1 Pa

Hence, $p=4*10^{2} Ba$