Question

breaks applied to a car produce an acceleration of 6m/s sq. in opposite direction to motion if the car takes 2s to stop after application of brakes then calculate the distance it travels during this time

Answer 1

v = u+at
v= final velocity u = initial velocity a= acceleration t = time
given v= 0 a= - 6 opposite direction t= 2
u== 12 m/s
s=ut + 1/2at2
s = 12*2 +1/2*-6*-6
answer = 44m

Answer 2

i hope this will help you