Question

breaks applied to a car produce an acceleration of 6m/s sq. in opposite direction to motion if the car takes 2s to stop after application of brakes then calculate the distance it travels during this time

Answer 1

Hope you get the answer

Answer 2

Here, a = -6 m/s, t = 2sec, v = 0 m/s, s =?
By applying,
v = u + at
0 = u + (-6) 2
u = 12 m/s
Now, by applying,
s = ut + 1/2at^2
= 12*2 + (1/2)(-6)2^2 m
= 24 - 12 m
= 12m