Math, asked by Syrien10, 11 months ago


Brian buys a computer for £2100.
It depreciates at a rate of 1% per year.
How much will it be worth in 6 years?
Give your answer to the nearest penny where appropriate.

Answers

Answered by js403730
1

Answer:

Brian buys a computer for £2100.

It depreciates at a rate of 1% per year.

How much will it be worth in 6 years?

Give your answer to the nearest penny where appropriate.

Answered by abhinavraj980161
3

\huge\mathcal{Heya!}

Here's your answer⤵️⤵️⤵️

 \orange{  \tt: { \therefore{price \: of \: computer \: after \: 6th \: year = £1977.1}}}

\green{\underline \bold{given :}}\\  \tt :\implies \: price \: of \: computer =  2100 \\  \\  \tt: \implies depreciate \:rate\%= 1\\\  \\ \red{\underline \bold{to \: find}} \\  \tt: \implies price \: of \: computer \: after \: 6 \: year

According to the question

 \bold{as \: we \: know \: that :} \\  \tt:  \implies 1st \: year \: depreciate \: price = 2100 - 2100 \: of \: 1\% \\  \\ \tt:  \implies 1st \: year \: depreciate \: price = 2100 - 2100 \times  \frac{1}{100}  \\  \\ \tt:  \implies 1st \: year \: depreciate \: price = 2100 - 21 \\  \\ \tt:  \implies 1st \: year \: depreciate \: price =  £2079 \\  \\  \bold{for \: 2nd \: year : } \tt:  \implies 2nd \: year \: depreciate \: price = 2079 - 1\% \: of \: 2079 \\  \\ \tt:  \implies 2nd \: year \: depreciate \: price = 1977.1083077421 \\  \\ \green {\tt:  \implies 6th\: year \: depreciate \: price =  £1977.1}

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