Question

Brian buys a computer for £4300. It depreciates at a rate of 3% per year. How much will it be worth in 6 years? Give your answer to the nearest penny where appropriate.

Answer 1

Answer:

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Answer 2

Answer

$\green{\tt{\therefore{Price\:of\:computer\:after\:6\:year=\pounds1977.1}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\red{\underline \bold{To \: Find :}} \\ \tt: \implies Price \: of \: computer \: after \: 6 \: year =? \end{gathered}$

To Find:

:⟹Priceofcomputer=£2100

:⟹Depreciaterate%=1%

:⟹1st year depreciate price=2100−2100of1%

:⟹1styeardepreciateprice=2100−2100×

100

1

:⟹1st year depreciate price=2100−21

:⟹1st year depreciate price=£2079

$\frac{1}{100} \times 2079 \\ \\ \tt: \implies 2nd\: year \: depreciate \: price =2079 - 20.79 \\ \\ \tt: \implies 2nd\: year \: depreciate \: price = \pounds 2058.21 \\ \\ \bold{Similarly : } \\ \tt: \implies 3rd\: year \: depreciate \: price =2058.21 - 1\% \: of \: 2058.21\end{gathered}$

$\\ \tt: \implies 4th \: year \: depreciate \: price = 2037.6279 - 20.376279 \\ \\ \tt: \implies 4th \: year \: depreciate \: price =\pounds 2017.251621 \\ \\ \bold{For \: 5th \: year : } \\ \tt: \implies5th \: year \: depreciate \: price =2017.251621 - 20.17251621 \\ \\ \tt: \implies 5th \: year \: depreciate \:$

$\\ \\ \bold{For \: 6th \: year : }\\ \tt: \implies 6th \: year \: depreciate \: price = 1997.07910479 - 19.9707910479 \\ \\ \tt: \implies 6th\: year \: depreciate \: price =1977.1083077421 \\ \\ \green{\tt: \implies 6th\: year \: depreciate \: price = \pounds 1977.1}\end{gathered}$

Thanks!