Question

Brian, William, John and Smith are four friends. The sum of the ages of all of them 171 One
ago, the age of John was twice that of Brian. After one year, the age of Smith would be
William. What would be the sum of the ages of Brian and William after three years​

Answer 1

Answer:

The sum of the ages of Brian and William after three years would be:

(x + 3) + (y + 3) = 27 + 3 + 35 + 3 = 68

So, the answer is 68.

Step-by-step explanation:

Let's use algebra to solve the problem:

Let x be the age of Brian, y be the age of William, z be the age of John, and w be the age of Smith.

From the problem, we have the following equations:

x + y + z + w = 171 (equation 1)

z - 1 = 2(x - 1) (equation 2)

w + 1 = y + 1 (equation 3)

Simplifying equation 2, we get:

z = 2x - 1

Substituting this into equation 1, we get:

x + y + 2x - 1 + w = 171

3x + y + w = 172 (equation 4)

Substituting equation 3 into equation 4, we get:

3x + (w + 1) + w = 172

3x + 2w + 1 = 172

3x + 2w = 171

Now we need another equation to solve for x and y. Let's use the fact that after one year, the sum of their ages will be 171 + 4 = 175.

So, we have:

(x + 1) + (y + 1) + (z + 1) + (w + 1) = 175

x + y + z + w + 4 = 175

x + y + 2x - 1 + w + 4 = 175

3x + y + w = 172 (equation 4, which we derived earlier)

Solving equations 3 and 4 simultaneously, we get:

w = 35, y = 35, x = 27, z = 75

Therefore, the sum of the ages of Brian and William after three years would be:

(x + 3) + (y + 3) = 27 + 3 + 35 + 3 = 68

So, the answer is 68.

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