Brick is 30cm long, 10 cm wide and 10 cm thick. It weights 24N
and is lying on the ground. Find the pressure exerted by the brick on the ground.
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Brick is 30cm long, 10 cm wide and 10 cm thick. It weights 24N and is lying on the ground. Find the pressure exerted by the brick on the ground.
Here, force (F) = 24N
Area (A) of contact ( l × 6 ) between the brick on the ground
= 30cm × 10 cm
= 0.3m × 0.1m = {0.03}^{2}m
We know pressure (P) = \frac{Force(F)}{Area(A)}
So, P = \frac{24N}{0.03}^{2}m
= 800 {N/m}^{2} or 800 Pa
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