History, asked by advaitadvika999, 1 month ago

Brick is 30cm long, 10 cm wide and 10 cm thick. It weights 24N
and is lying on the ground. Find the pressure exerted by the brick on the ground.

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Answered by InstaPrince
1

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Answered by advaitjoshi699
3

\Large\underbrace \frak\red{Question}

Brick is 30cm long, 10 cm wide and 10 cm thick. It weights 24N and is lying on the ground. Find the pressure exerted by the brick on the ground.

\Large\underbrace \frak\red{Answer}

 {\underline{ \underline{ \pink{800  \: {N/m}^{2}  \: or \:  800 \:  Pa}}}}

\Large\underbrace \frak\red{solution}

Here, force (F) = 24N

Area (A) of contact ( l × 6 ) between the brick on the ground

= 30cm × 10 cm

= 0.3m × 0.1m = {0.03}^{2}m

We know pressure (P) = \frac{Force(F)}{Area(A)}

So, P = \frac{24N}{0.03}^{2}m

= 800 {N/m}^{2} or 800 Pa

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