bridge. 16. A train passes two bridge of lengths 210m and 122m in 25 sec and 17 sec respectively. Let us calculate the lenth and speed of the train. moining at a speed of 48 km/hr passes a tunnel in 21 sen
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let length of the train be L and speed S
(210+L)/S=25 1st equation
(122+L)/S=17 2nd equation
210+L=25S 3rd equation
122+L=17S 4th equation
Subtract 4th equation from 3rd equation
88=8S
S=88/8=11
Put this value of S in any of the above equations
you will get the value of L
122+L=17×11=187
L=187-122=65
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