Question

Bridget is 5 years older than Angad. Paul is 4 years younger than Angad. If the total of their ages is 49, how old is the eldest of them?

Answer 1

Answer:

21 years old

Step-by-step explanation:

let angad's age=x

therefore, bridget is x+5 years old

and paul is x-4 years old

a/q

x+x+5+x-4=49

3x -1=49

3x=48

x=16

x+5 = 21

x-4=12

Answer 2

Given:-

• The age of Bridget=Angad+5 years
• The age of Paul=4 years younger than Angad
• The total sum of their ages are 49

Let:-

• The age of Angad be X

To Find:-

• Who is the eldest of them?

According to the above information:-

• The age of Paul=X-4 years
• The age of Angad=X years
• The age of Bridget=X+5

=>Sum of their ages=49

==>X+5+X-4+X=49

==>3X+1=49

==>3X=49-1

==>3X=48

==>X=16

Hence,

The age of Bridget=X+5=16+5=21 years

The age of Angad=X=16 years

The age of Paul=X-4=16-4=12 years

Verification:-

=Sum of their ages=49

=21+16+12=49

=49=49

Hence, Verified

Answer:-

• The Bridget's age is oldest among them