BRILLIANT PLZ ANSWER
3rd QUESTION
NO SPAM PLZ
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1
the question is just like this one
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MrUnfamiliar:
ull have to frame it like this
let the length be x and breadth be y and go on for the area to be xy
then add the changes
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To find:-
The dimensions of the rectangle
SOLUTION:-
Let:- Length=1unit
Breadth=b units
And Area=1×b units
1 case:-( when length increased by 5 units and breadth decreased by 3 units)
Area = Length × Breadth
======>(lb-25)=(l+5)(b-3)
======>lb-25=lb-3l+5b-15
======>3l-5b=10---(i)
2nd case:- (when length increased by 2 units and breadth increased by 5 units)
Area= length × breadth
======>lb+285= (l+2)(b+5)
======>lb+285=lb+5l+2b+10
=====>5l+2b=275-----(ii)
FROM (i) we get
l= 5b+10/3
NOW subtituting 1 value in i
we get
5(5b+10/3)2b=273
25b+50+6b=825
31b=775
b=25
l=5(25)+10/3=135/3=45 units
l=45
The dimensions of the rectangle
SOLUTION:-
Let:- Length=1unit
Breadth=b units
And Area=1×b units
1 case:-( when length increased by 5 units and breadth decreased by 3 units)
Area = Length × Breadth
======>(lb-25)=(l+5)(b-3)
======>lb-25=lb-3l+5b-15
======>3l-5b=10---(i)
2nd case:- (when length increased by 2 units and breadth increased by 5 units)
Area= length × breadth
======>lb+285= (l+2)(b+5)
======>lb+285=lb+5l+2b+10
=====>5l+2b=275-----(ii)
FROM (i) we get
l= 5b+10/3
NOW subtituting 1 value in i
we get
5(5b+10/3)2b=273
25b+50+6b=825
31b=775
b=25
l=5(25)+10/3=135/3=45 units
l=45
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