Math, asked by Anonymous, 6 months ago

.bro...explain.....
.....

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Answered by utkarshkumarhld33

1

Answer:

RHS

sin²A/(1-CosA). [sin²=1-Cos²A]

(1-Cos²A)/(1-CosA). [a²-b²=(a+b)(a-b]

[(1+CosA)(1-CosA)]/(1-CosA)

1+CosA. [CosA=1/SecA]

1+1/SecA

(SecA+1)/SecA

Proved

Answered by Anonymous

1

very simple question...

see figure in attachment

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