Question

BRO/SISTER
A PARTICLE COVERS 10 METERS IN FIRST 5 SECONDS AND 10 METERS IN NEXT 3 SECONDS .ASSUMING CONSTANT ACCELERATION. FIND THE INITIAL SPEED, ACCELERATION AND DISTANCES COVERED IN NEXT 2 SECCONDS

ANSWER FAST AS YOUR POSSIBLE

Answer 1

Answer:

don't know

plz fallow me

Answer 2

Answer:

It is given that a particle covers 10m in first 5s and 10m in next 3s. so using the equation of motion

Case I

s=ut+ 1/2at2

10=5u+ 1/2 a (5)^2

20=10u+25a

4=2u+5a..............(1)

Case 2

In next 3s the particle covers more 10m distance. So

20=8u+ 1/2 a(8)^2

5=2u+8a.........(2)

On solving equation (1) and (2)

4=2u+5a

5=2u+8a

a= 1/3 m/s2

Put the value of a in equation (1)

u= 7/6 m/s

Now to find distance in next 10 s. total time will be 10s

s= (7/6)*10+(1/2)*(1/3)*(10)^2

s=28.33m

Distance travelled in next 2 sec

s=28.33−20=8.33