Question

Bro solve this question also.


From the above figure
1. Find the deceleration of the body in the region BC.
2. Find the total distance travelled by the body.

Given, v is in m s^-1 and time in s.

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Answer 1

$answer$

1)))Slope of BC gives you acceleration of the body in the region BC.

Slope=

$\frac{10 - 5}{ - 4 + 3} = - 5m \: per \: {s}^{2}$

2)))Area of velocity time graph gives distance traveled.

Area of triangle ABC =10m

Area of rectangle CDEF=5m

Distance traveled=15m.

Answer 2

Answer:

1. Deceleration = slope of BC = (10 - 5) m s^-1 /( 4 -3 ) s = 5 m s^-2

2. Total distance travelled = Area of the triangle ABC + Area of rectangle 0ADE = 1/2 AC × BC + AD × DE

S = {1/2 × 4 × 5} + (5 × 5) = 35 m

Explanation:

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