Bromine will only react with propane in sunlight, but bromine reacts quickly with propene without sunlight.
Using appropriate notation and equations, explain the steps involved in the mechanism of the chemical reaction of bromine with propane (in sunlight) OR bromine with propene
(without sunlight)
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Answer:
In common with all other alkenes, propene reacts in the cold with pure liquid bromine, or with a solution of bromine in an organic solvent like tetrachloromethane. ... The bromine loses its original red-brown colour to give a colourless liquid. In the case of the reaction with propene, 1,2-dibromopropane is formed.
Explanation:
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Propene is a lot more reactive than propane as it has a C=C. Propane has no double bond and thus is saturated. So, propane requires high energy source like sunlight to take part in reactions like halogenation. But propene easily reacts with bromine to form di-bromo propane.
Explanation:
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