Question

bromo ethane to propanol​

Answer 1

Answer:

CH

3

−CH

2

−Br

KCN

CH

3

−CH

2

−CN

↓H

2

O

DiBAL−H

Proponal

CH

3

−CH

2

−CHO

In first step Nucleophilic substitution of −CN group take place as Br

⊝

is a good leaving group. Then on an addition of H

2

O in presence of DiBAL−H, partial hydrolysis takes place and we get aldehyde. DiBAL−H is a reducing agent.

Explanation:

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