bromoethane on reaction with aqueous KoH form ethanol where as alcohol Koh form ethene explain with equation
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Aqueous KOHKOH is alkaline in nature i.e. it dissociates to produce a hydroxide ion. These hydroxide ions act as a strong nucleophile and replace the halogen atom in an alkyl halide.
RCl+KOH(aq)⟶ROH+KClRCl+KOH(aq)⟶ROH+KCl
This results in the formation of alcohol molecules and the reaction is known as nucleophilic substitution reaction.
Alcoholic, KOHKOH, specially in ethanol, produces C2H5O−CX2HX5OX− ions. The C2H5O−CX2HX5OX−ion is a stronger base than the OH−OHX− ion. Thus,the former abstracts the ß-hydrogen of an alkyl halide to produce alkenes.
RCl+KOH(aq)⟶ROH+KClRCl+KOH(aq)⟶ROH+KCl
This results in the formation of alcohol molecules and the reaction is known as nucleophilic substitution reaction.
Alcoholic, KOHKOH, specially in ethanol, produces C2H5O−CX2HX5OX− ions. The C2H5O−CX2HX5OX−ion is a stronger base than the OH−OHX− ion. Thus,the former abstracts the ß-hydrogen of an alkyl halide to produce alkenes.
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Answer:
bromo ethane on reaction with KOH gives KBr +C2H5Br
please remember alcoholic KOH gives C2H4+KBr+H2O
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