Question

bromoform has a normal freezing point of 7.734°C/m and it's K. = 14.4C/m. A solution of
2.60 g of a unknown in 100 g of bromoform freezes at 5.43°C. What ithe molecular weight of the unknown
1...16.25
(2) 162.5
(C) 100
(d) none of these​

Answer 1

Answer:

161.86 grams/mole

Explanation:

The formula for depression of freezing point of solutions is :

T2-T1=Kf(m)

Where m is morality and Kf is depression constant

Molality(m)= no of moles of solute/kg of solvent

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