Question

Brown eyes are dominant (B) to blue (b). A brown-eyed man whose mother was blue-eyed married a brown-eyed woman whose father had blue eyes. What is the probability that the couple will have a blue-eyed child?
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Answer 1

Answer:

Hi mate

Explanation:

The brown eye form of the eye color gene (or allele) is dominant, whereas the blue eye allele is recessive. If both parents have brown eyes yet carry the allele for blue eyes, a quarter of the children will have blue eyes, and three quarters will have brown eyes.

Answer 2

Answer:

Your partners are both heterozygous for the pigment-producing gene that makes the iris brown. Each had a parent devoid of the pigment gene, so neither could have inherited a pigment gene from both parents. Call the dominant pigment allele B and the inactive allele b. The man and woman are both Bb - one of each allele. It only takes one B allele to give brown eyes. Each parent gives a child one allele.

Explanation:

BB (brown eyes)

Bb (brown eyes)

bB (brown eyes)

bb (blue eyes)

Therefore your answer is a 1:4 chance of having a blue-eyed child.