Question

btao pls maths questions hai​

Answer 1

Answer:

Angle BCD=60°

Step-by-step explanation:

Given:A cyclic trapezium ABCD

ABC: 60°

AD||BC

To find: Angle BCD

Solution:

ABC+ADC=180°(Opposite angles of a cyclic quadrilateral are supplementary)

60°+ADC=180°

ADC=180-60

ADC=120°

Since, AD||BC

DC is a transversal

Therefore, ADC+BCD=180°( Cointerior angles)

120+BCD=180

BCD=180-120

BCD=60°

Hope it helps! :)

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