bucket containing 8 kg of water at 20 degree celsius when 4 kg of water is mixed with it the temperature of the mixture becomes 40 degree celsius calculate the temperature of hot water
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Answer:
Specific heat capacity of water=4200 J/kgK
By the principle of mixtures,
m x c (T1-T) = m x c x(T-T2)
2 x 4200(80-T) = 8 x 4200(T-25)
(4200 on both sides get cancelled)
160-2T = 8T-200
360 = 10T
T= 36 degree Celcius
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