Buffalo gives 4 litre milk,cow 500 ml,and sheep gives 250 ml milk so total count of cattle is 20..and total litter of milk also 20..how to possible it?
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Assume number of respective animals are x,y,z.
x+y+z=20---(1) as the total number of animal has to be 20
Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)
Solving equation 1 and 2 we get
15x+y=60 ----(3)
Since buffalo gives 4litre and total milk is 20, x < 5
But from eq 3, x cannot be more than 4;
Further if x=1 or 2; y>20... Not possible, since total animal is 20
Thus, x=3, y=15, z=2
Ans: 3 buffalos, 15cows, 2goats
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