Question

बड़ी से बड़ी संख्या बताइए जिससे 49 ,59 और 109 भाग देने पर क्रमशः 1,3और 5 शेष रहे
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Answer 1

Answer:

first minus their remainder

49-->49-1=48

59-->59-3=56

109-->109-5=104

now find the HCF of 48,56,104

48=2×2×2×2×3

56=2×2×2×7

104=2×2×2×13

HCF is 8

hence 8 is the no. which divide 49,59,109 and leaves remainder 1,3,5 respectively

Answer 2

Answer:

Step-by-step explanation: