Question

bulb of resistance 200 Q is connected to a 10 V battery. The power consumptions​

Answer 1

Answer:

0.5 watts

Explanation:

Given :

Resistance of the bulb Q = R = 200 ohms

Voltage or the potential difference = v = 10 volts

To find :

Power consumption of the bulb

Using the ohms law :

V=I×R

10=I×200

I=10/200

I=0.05

Power = V×I

So Substituting the values :

Power = 10×0.05

Power = 0.5 watts

The power consumption is equal to 0.5 watts

Answer 2

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Bulb of resistance 200 Q is connected to a 10 V battery. The power Consumptions..

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✎Given :

$\implies{Resistance(R)\:of\:Bulb(Q) = 200Q}$

$\implies{Potential\:Difference = 10\:Volts}$

✎To Find :

$\implies{Power\:Consumption\:of\:the\:bulb=?}$

✎Here :

• V = 10
• R = 200

✎Formula Used :

$\implies{{ \small{ \bold{ \bold{ \bold{ \pink{V=I\times{R}}}}}}}}$

$\implies{10=I\times{200}}$

$\implies{10=200\:l}$

$\implies{I=\cancel\dfrac{10}{200}}$

$\implies{I=0.05}$

✎Now,

$\implies{Power=V\times{I}}$

$\implies{Power=10\times{0.05}}$

$\implies{Power=0.5W}$

✎So, the power consumption of the bulb is 0.5 Watt..