Question

Bulk modulus of water is (2.3xx10^(9) N//m^(2)).Taking average density of water rho=10^(3)kg//m^(3),find increases in density at a depth of 1 km. Take g=10m//s^(2)

Answer 1

Increases in density at a depth of 1 km

= 4.34 kg/m³

Given:

Bulk modulus of water is 2.3x$10^9$ N/m²

Average density of water = $10^3$ kg/m³

To find:

Increases in density at a depth of 1 km.

Formula used:

Bulk modulus = $\frac{\rho\Delta P }{\Delta \rho }$

Where    $\Delta P$ = Change in pressure

              $\Delta \rho$ = change in density

                $\rho$ = density.

Explanation:

H = height = 1km = 1000 meter.

For water  $\Delta P$ = Change in pressure = $\rho g h$ = $10^3$ × 10 × 1000

                            Change in pressure = $10^7$

Bulk modulus = $\frac{\rho\Delta P }{\Delta \rho }$

          2.3x$10^9$ = $\frac{10^7 \times 10^3 }{\Delta \rho }$

                      $\Delta \rho$ = $\frac{10^7 \times 10^3 }{2.3 \times 10^9 }$

Increases in density at a depth of 1 km = 4.34 kg/m³

To learn more....

1)The bulk modulus of copper is 138 into 10 ki power 9 Pascal the additional pressure generated and expansion chamber this 345 into 10 ki power 6 Pascal the percentage in the volume of piece of copper plates the Chamber will be​.

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