Question

Bulk modulus of water is 2 x 10^9 Nm^2-The change in pressure required to increase the density of water
by 0.1% is
(A) 2 x 10^9 Nm^2
(B) 2x10^8 Nm^2
(C) 2x10^6 Nm^2
(D) 2x10^4 Nm ^2​

Answer 1

Answer:

Let d = density

d = m / V

d (d) = -m dV / V^2     differential change in density

d (d) / d = - dV / V dividing equations

d (d) / d = .001   = dV / V fractional change in density

B = - dP / (dV / V)

dP = B * dV / V = 2 * 10E9 * .001 = 2 * 10E6