Question

Bulk modulus of water is 2 x 105 N/m2. The change in pressure required to
increase density of water by 0.1% is
1
2 x 10^9 newton/metre^2
2 2 x 10^8 newton/metre?
3 2 x 10^2 newton/metre^2
4 2 x 10^4 newton/metre?​

Answer 1

Answer:

Answer

B=−VdVdP

Thus, ΔV=−BΔpV, where p is change in pressure.

Thus, V′−V=−BΔpV or, V′=V(1−BΔp)

Now, ρ′=V′m=V(1−BΔp)m=(1−BΔp)ρ

Given ρ′=1.001ρ, or 1.0011=1−2×109p

or, Δp=10011×2×109, which is nearly 2×106