Question

Bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates thick wooden plank of mass 90 g.The plank was initially at rest. The bullet get embedded in the plank and both move together. Determine their velocity.

Answer 1

Given : mass of bullet= 10g= 0.01kgvelocity of bullet= 1.5m/smass of plank= 90g=0.09kgTotal momentum before collision=mass of plank x velocity=0.01x1.5+0.09x0=0.015 kgm/sTotal momentum after collision=(mass of bullet +mass of plank )x velocity=0.1 kg x V=0.1 V kgm/sAccording to law of conservation of momentum,Total momentum before collision=Total momentum after collision0.015kg m/s =0.1 v kg m/s
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