Physics, asked by AkshitAhlawat7707, 1 year ago

Bullet initially moving with a velocity of 20 m per second strikes targeted comes to rest after penetrating a distance of 0.01 m in the target calculate the retardation produced by the target

Answers

Answered by vIsHal005
2
Hop you get the answer
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Answered by Anonymous
44

Given : -

  • Initial velocity of the bullet, u = 20 m/s
  • Final velocity of the bullet, v = 0 m/s
  • Distance, s = 0.01 m

To find : -

  • Retardation produced by the target=?

Solution : -

\qquad ☀️To calculate it we will use the third equation of motion.We know that third equation of motion :-

\qquad\pink{\pmb  {\mathfrak{v² - u² = 2as}}}

Where:-

  • v = Final velocity
  • u = Initial velocity
  • a = Acceleration
  • s = Distance

\qquad\small\underline{\pmb{\sf Substituting \: the\:  given\:  values \::-}}

\qquad\leadsto\quad \pmb  {\mathfrak{ (0)² - (20)² = 2(a)(0.01)}}\\

\qquad\leadsto\quad \pmb  {\mathfrak{ - (20)² = 2 × a × 0.01}}\\

\qquad\leadsto\quad \pmb  {\mathfrak{ - 400 = 2 × a × 0.01}}\\

\qquad\leadsto\quad \pmb  {\mathfrak{ - 400 ÷ (2 × 0.01) = a}}\\

\qquad\leadsto\quad \pmb  {\mathfrak{ - 20,000 = a}}\\

\pink{\qquad\leadsto\quad \pmb  {\mathfrak{ a = - 20,000 m/s²}}}\\

(Negative acceleration is known as retardation.)

Therefore, the retardation of the bullet is 20,000 m/s²

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\qquad ☀️Equations of motion :-

\qquad ⑴ v = u + at

\qquad ⑵ s = ut + ½at²

\qquad ⑶ v² - u² = 2as

  • v = final velocity
  • u = initial velocity
  • s = displacement
  • t = time taken
  • a = acceleration

\\

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