Question

Bullet leaves Rifle with the muzzle velocity of 1042 m/s while accelerating to the barrel of rifle the bullet moves distance of 1.680m determine the acceleration of the bullet (assume uniform acceleration)

Answer 1

Hey friend

here is your answer

given initial velocity is 0
and final velocity is 1042m/s
distance given =1.68 m


v²= U² + 2as

(1042)² = 0 +2a(1.68)

1085764 = 0 +3.36a

its acceleration become

=> 323144 m/s²


Hope it help

Thank you