bullet of mass 0.02 kg is fired from a gun of mass 10 kg. If recoil velocity of the gun is 0.4 m/s then what is the initial velocity of the bullet? (write in SI unit, no need to write the unit)
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Answer :
›»› The velocity of bullet is 200 m/s.
Given :
- Bullet of mass 0.02 kg is fired from a gun of mass 10 kg. If recoil velocity of the gun is 0.4 m/s.
To Calculate :
- The initial velocity of the bullet?
Calculation :
- Mass of bullet (m₁) = 0.02 kg
- Mass of gun (m₂) = 10 kg
- Velocity of gun (v₂) = 0.4 m/s
- Initial velocity of bullet (v₁) = ?
We can find velocity of bullet by using the law of conservation of moment which says m₁v₁ = m₂v₂
From law of conservation of moment
→ m₁v₁ = m₂v₂
→ 0.02 * v₁ = 10 * 0.4
→ 0.02v₁ = 10 * 0.4
→ 0.02v₁ = 4
→ v₁ = 4/0.02
→ v₁ = 200
║Hence, the velocity of bullet is 200 m/s.║
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