Question

bullet of mass 0.02 kg is fired from a gun weighing 8 kg . if the initial velocity of the bullet is 200 m/s . calculate recoil speed of gun

Answer 1

Answer:

0.5 m/s

Explanation:

acc to Newton second law

m1v1=m2v2

0.02 *200=8*v2

v2= 4/8=0.5m/s

Answer 2

Answer:

m1×v1=m2×v2

0.02×200=8×v2

4/8=v2

v2=0.5

hope it works