Question

bullet of mass 1 gm is fired with a velocity of 300 ms-1. Find its K E.​

Answer 1

Answer:

if A bullet of mass 10 g is fired from a rifle. The bullet takes 0.003 s to move through its barrel and leaves with a velocity of 300ms

−1

. What is the force exerted on the bullet by the rifle?

Explanation:

1000 N

v=300 ms

−1

; u=0 ,t=0.003 s ,m=0.01 kg

Force exerted by the bullet on the rifle =

time

m(v−u)

F=1000 N

Answer 2

Let the recoil velocity of gun be V.

Mass of gun M gun =5.0 kg

Mass of bullet M bullet=0.01 kg

Velocity of bullet V bullet =250 m/s

Initial momentum of the system P i=0

Applying the conservation of linear momentum : P f =P i

Or

Mgun V + M bullet V bullet =0

Or 5×V+0.01×250=0

⟹ V=−0.5 m/s