Social Sciences, asked by yovasuyo, 1 year ago

bullet of mass 10g is fired with a rifle. The bullet takes 0.003s to move through its barrel and leaves it with a

velocity of 300m/s. What is the force exerted on the bullet by the rifle.

Answers

Answered by UnknownDude
65
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The mass of the bullet (m) = 0.01 kg
Its initial velocity (u) = 0, as it was at rest before being fired.
Its final velocity (v) = 300 m/s
Time taken = 0.003 s
a =  \frac{v - u}{t}  \\  =  \frac{300 - 0}{0.003}  \\  =  \frac{300 \times 1000}{3}  \\  = 100000
Acceleration of the bullet is 100000 m/s²
Force = mass × acceleration
= 0.01 kg × 100000 m/s²
= 1000 N
The firce exerted by the rifle on the bullet will be 1000 N.

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Answered by ramadevi70206
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