Question

bullet of mass 40gm is fired from a gun of mass 8kg with a velocity of 800 m/s, calculate the recoil velocity of gun
​

Answer 1

Answer:

M=40gm=0.40kg

8kg

Final.V=800m/s

Initial.V=?

ma

m mulitly by a

0.40 by 8kg by 800m/s

25600

Answer 2

Step-by-step explanation:

Given, for bullet

mass of the bullet, m1 = 40g = 0.04 kg

initial velocity of the bullet, u1 = 0 m/s

final velocity of the bullet, v1 = 800 m/s

for pistol,

mass of the pistol, m2 = 8 kg

initial velocity of the gun, u2 = 0 m/s

final velocity of the gun, v2 = ?

Now,

we will find out according to the law of conservation of momentum.

Total momentum before the fire = Total momentum after the fire

m1 u1 + m2 u2 = m1 v1 + m2 v2

0.04×0 + 8×0 = 0.04×800 + 8×v2

0 = 32 + 8 v2

- 32 = 8v2

-32/8 = v2

-4 = v2

v2 = -4 m/s

Negative sign indicates that the direction in which the pistol would recoil is opposite to that of bullet.